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	Correct partial pressure calculations
Regardless what the dive computer tells us, don't believe that pO2 was higher than the ambient pressure. This gives much more realistic values. Signed-off-by: Dirk Hohndel <dirk@hohndel.org>
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					 1 changed files with 4 additions and 2 deletions
				
			
		|  | @ -1879,9 +1879,11 @@ static struct plot_info *create_plot_info(struct dive *dive, struct divecomputer | |||
| 			/* we have an O2 partial pressure in the sample - so this
 | ||||
| 			 * is likely a CC dive... use that instead of the value | ||||
| 			 * from the cylinder info */ | ||||
| 			double po2 = entry->po2 > amb_pressure ? amb_pressure : entry->po2; | ||||
| 			double ratio = (double)fhe / (1000.0 - fo2); | ||||
| 			entry->phe = (amb_pressure - entry->po2) * ratio; | ||||
| 			entry->pn2 = amb_pressure - entry->po2 - entry->phe; | ||||
| 			entry->phe = (amb_pressure - po2) * ratio; | ||||
| 			entry->pn2 = amb_pressure - po2 - entry->phe; | ||||
| 			entry->po2 = po2; | ||||
| 		} else { | ||||
| 			entry->po2 = fo2 / 1000.0 * amb_pressure; | ||||
| 			entry->phe = fhe / 1000.0 * amb_pressure; | ||||
|  |  | |||
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