Cleanup: remove merge_two_dives() function

In 014c04f8bd merging dives was included
in the undo-system. This made the merge_two_dives() function caller-less.
Remove it.

Signed-off-by: Berthold Stoeger <bstoeger@mail.tuwien.ac.at>
This commit is contained in:
Berthold Stoeger 2018-12-09 13:04:03 +01:00 committed by Dirk Hohndel
parent a597929c10
commit 10c20babae
2 changed files with 0 additions and 83 deletions

View file

@ -32,7 +32,6 @@
* void delete_single_dive(int idx)
* void add_dive_to_table(struct dive_table *table, int idx, struct dive *dive)
* void add_single_dive(int idx, struct dive *dive)
* struct dive *merge_two_dives(struct dive *a, struct dive *b)
* void select_dive(struct dive *dive)
* void deselect_dive(struct dive *dive)
* void mark_divelist_changed(int changed)
@ -1183,87 +1182,6 @@ bool consecutive_selected()
return consecutive;
}
/*
* Merge two dives. 'a' is always before 'b' in the dive list
* (and thus in time).
*/
struct dive *merge_two_dives(struct dive *a, struct dive *b)
{
struct dive *res;
int i, j, nr, nrdiff;
int id;
if (!a || !b)
return NULL;
id = a->id;
i = get_divenr(a);
j = get_divenr(b);
if (i < 0 || j < 0)
// something is wrong with those dives. Bail
return NULL;
res = merge_dives(a, b, b->when - a->when, false, NULL);
if (!res)
return NULL;
/*
* If 'a' and 'b' were numbered, and in proper order,
* then the resulting dive will get the first number,
* and the subsequent dives will be renumbered by the
* difference.
*
* So if you had a dive list 1 3 6 7 8, and you
* merge 1 and 3, the resulting numbered list will
* be 1 4 5 6, because we assume that there were
* some missing dives (originally dives 4 and 5),
* that now will still be missing (dives 2 and 3
* in the renumbered world).
*
* Obviously the normal case is that everything is
* consecutive, and the difference will be 1, so the
* above example is not supposed to be normal.
*/
nrdiff = 0;
nr = a->number;
if (a->number && b->number > a->number) {
res->number = nr;
nrdiff = b->number - nr;
}
add_single_dive(i, res);
delete_single_dive(i + 1);
delete_single_dive(j);
// now make sure that we keep the id of the first dive.
// why?
// because this way one of the previously selected ids is still around
res->id = id;
// renumber dives from merged one in advance by difference between
// merged dives numbers. Do not renumber if actual number is zero.
for (; j < dive_table.nr; j++) {
struct dive *dive = dive_table.dives[j];
int newnr;
if (!dive->number)
continue;
newnr = dive->number - nrdiff;
/*
* Don't renumber stuff that isn't in order!
*
* So if the new dive number isn't larger than the
* previous dive number, just stop here.
*/
if (newnr <= nr)
break;
dive->number = newnr;
nr = newnr;
}
mark_divelist_changed(true);
return res;
}
void select_dive(struct dive *dive)
{
if (!dive)

View file

@ -36,7 +36,6 @@ extern dive_trip_t *create_and_hookup_trip_from_dive(struct dive *dive);
extern dive_trip_t *get_dives_to_autogroup(int start, int *from, int *to, bool *allocated);
extern dive_trip_t *get_trip_for_new_dive(struct dive *new_dive, bool *allocated);
extern void autogroup_dives(void);
extern struct dive *merge_two_dives(struct dive *a, struct dive *b);
extern bool consecutive_selected();
extern void select_dive(struct dive *dive);
extern void deselect_dive(struct dive *dive);