Import: merge dives trip-wise

The old way of merging log-files was not well defined: Trips
were recognized as the same if and only if the first dives
started at the same instant. Later dives did not matter.

Change this to merge dives if they are overlapping.
Moreover, on parsing and download generate trips in a separate
trip-table.

This will be fundamental for undo of dive-import: Firstly, we
don't want to mix trips of imported and not-yet imported dives.
Secondly, by merging trip-wise, we can autogroup the dives
in the import-data to trips and merge these at once. This will
simplify the code to decide to which trip dives should be
autogrouped.

Signed-off-by: Berthold Stoeger <bstoeger@mail.tuwien.ac.at>
This commit is contained in:
Berthold Stoeger 2018-12-23 12:46:45 +01:00 committed by Dirk Hohndel
parent f542dc4030
commit 1593f2ebad
13 changed files with 251 additions and 129 deletions

View file

@ -2555,25 +2555,10 @@ static void merge_temperatures(struct dive *res, const struct dive *a, const str
MERGE_NONZERO(res, a, b, watertemp.mkelvin);
}
/*
* When merging two dives, this picks the trip from one, and removes it
* from the other.
*
* The 'next' dive is not involved in the dive merging, but is the dive
* that will be the next dive after the merged dive.
*/
static void pick_trip(struct dive *res, const struct dive *pick)
{
dive_trip_t *trip = pick->divetrip;
res->notrip = pick->notrip;
add_dive_to_trip(res, trip);
}
/*
* Pick a trip for a dive
*/
static const struct dive *get_preferred_trip(const struct dive *a, const struct dive *b)
static struct dive_trip *get_preferred_trip(const struct dive *a, const struct dive *b)
{
dive_trip_t *atrip, *btrip;
@ -2581,33 +2566,33 @@ static const struct dive *get_preferred_trip(const struct dive *a, const struct
atrip = a->divetrip;
btrip = b->divetrip;
if (!atrip)
return b;
return btrip;
if (!btrip)
return a;
return atrip;
/* Both dives have a trip - prefer the non-autogenerated one */
if (atrip->autogen && !btrip->autogen)
return b;
return btrip;
if (!atrip->autogen && btrip->autogen)
return a;
return atrip;
/* Otherwise, look at the trip data and pick the "better" one */
if (!atrip->location)
return b;
return btrip;
if (!btrip->location)
return a;
return atrip;
if (!atrip->notes)
return b;
return btrip;
if (!btrip->notes)
return a;
return atrip;
/*
* Ok, so both have location and notes.
* Pick the earlier one.
*/
if (a->when < b->when)
return a;
return b;
return atrip;
return btrip;
}
#if CURRENTLY_NOT_USED
@ -2903,14 +2888,6 @@ static int likely_same_dive(const struct dive *a, const struct dive *b)
same_string(b->dc.model, "manually added dive"))
return 0;
/* Don't try to merge dives with different trip information
* Exception: if the dive is downloaded without any
* explicit trip information, we do want to merge it
* with existing old dives even if they have trips.
*/
if (a->divetrip != b->divetrip && b->divetrip)
return 0;
/*
* Do some basic sanity testing of the values we
* have filled in during 'fixup_dive()'
@ -3403,7 +3380,6 @@ bool has_planned(const struct dive *dive, bool planned) {
struct dive *merge_dives(const struct dive *a, const struct dive *b, int offset, bool prefer_downloaded, struct dive_trip **trip)
{
struct dive *res = alloc_dive();
const struct dive *preferred_trip;
int cylinders_map_a[MAX_CYLINDERS], cylinders_map_b[MAX_CYLINDERS];
if (offset) {
@ -3424,11 +3400,8 @@ struct dive *merge_dives(const struct dive *a, const struct dive *b, int offset,
}
res->when = prefer_downloaded ? b->when : a->when;
res->selected = a->selected || b->selected;
preferred_trip = get_preferred_trip(a, b);
if (trip)
*trip = preferred_trip->divetrip;
else
pick_trip(res, preferred_trip);
*trip = get_preferred_trip(a, b);
MERGE_TXT(res, a, b, notes, "\n--\n");
MERGE_TXT(res, a, b, buddy, ", ");
MERGE_TXT(res, a, b, divemaster, ", ");