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gas model: add proper He compressibility data and do a least-squares fit
Lubomir pointed to exactly where he got his data from, so I added that raw Helium data to the R script, and let the least-squares fit just take care of the interpolation between 273K and 323K. Signed-off-by: Linus Torvalds <torvalds@linux-foundation.org> Signed-off-by: Dirk Hohndel <dirk@hohndel.org>
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@ -39,7 +39,6 @@ o2 = c(0.9994, 0.9968, 0.9941, 0.9884, 0.9771, 0.9676, 0.9597, 0.9542, 0.9560, 0
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n2 = c(0.9998, 0.9990, 0.9983, 0.9971, 0.9964, 0.9973, 1.0000, 1.0052, 1.0559, 1.1422, 1.2480, 1.3629)
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he = c(1.0005, 1.0024, 1.0048, 1.0096, 1.0191, 1.0286, 1.0381, 1.0476, 1.0943, 1.1402, 1.1854, 1.2297)
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options(digits=15)
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#
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@ -76,3 +75,41 @@ summary(hefit)
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new = data.frame(x = seq(min(x),max(x),len=200))
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lines(new$x,predict(hefit,newdata=new))
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#
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# Raw data from VOLUMETRIC BEHAVIOR OF HELIUM-ARGON MIXTURES [..]
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# T=323.15K (50 C)
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p323atm = c(674.837, 393.223, 237.310, 146.294, 91.4027, 57.5799, 36.4620, 23.1654, 14.7478, 9.4017, 5.9987, 3.8300,
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540.204, 319.943, 195.008, 120.951, 75.8599, 47.9005, 30.3791, 19.3193, 12.3080, 7.8495, 5.0100, 3.1992)
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Hez323 = c(1.28067, 1.16782, 1.10289, 1.06407, 1.04028, 1.02548, 1.01617, 1.01029, 1.00656, 1.00418, 1.00267, 1.00171,
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1.22738, 1.13754, 1.08493, 1.05312, 1.03349, 1.02122, 1.01349, 1.00859, 1.00548, 1.00349, 1.00223, 1.00143)
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# T=273.15 (0 C)
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p273atm = c(683.599, 391.213, 233.607, 143.091, 89.0521, 55.9640, 35.3851, 22.4593, 14.2908, 9.1072, 5.8095, 3.7083,
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534.047, 312.144, 188.741, 116.508, 72.8529, 45.9194, 29.0883, 18.4851, 11.7702, 7.5040, 4.7881, 3.0570)
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Hez273 = c(1.33969, 1.19985, 1.12121, 1.07494, 1.04689, 1.02957, 1.01874, 1.01191, 1.00758, 1.00484, 1.00309, 1.00197,
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1.26914, 1.16070, 1.09837, 1.06118, 1.03843, 1.02429, 1.01541, 1.00980, 1.00625, 1.00398, 1.00254, 1.00162)
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p323 = p323atm * 1.01325
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p273 = p273atm * 1.01325
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x2=append(p323,p273)
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he2=append(Hez323,Hez273)
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plot(x2,he2)
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hefit2 = nls(he2 ~ 1.0 + p1*x2 + p2*x2^2 + p3*x2^3,
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start=list(p1=0,p2=0,p3=0))
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summary(hefit2)
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he3 = function(bar)
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{
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1.0 +0.00047961098687979363 * bar -0.00000004077670019935 * bar^2 +0.00000000000077707035 * bar^3
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}
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new = data.frame(x2 = seq(min(x2),max(x2),len=200))
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lines(new$x2,predict(hefit2,newdata=new))
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curve(he3, min(x2),max(x2),add=TRUE)
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