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cleanup: don't NUL-terminate membuffer in uploadDiveLogsDE
The data of the membuffer is passed as a data/length pair to xmlReadMemory(). There is no point in NUL-terminating it. Moreover, pass the data directly to xmlReadMemory() instead of via variables. These variables are reused later with a different meaning, making this super-confusing. The membuf variable is turned from "const char *" to "char *" to signal that we own the buffer. Amazingly, zip_source_buffer() frees the buffer, even though a "const void *" is passed in. This API is pure madness. Add a comment. Signed-off-by: Berthold Stoeger <bstoeger@mail.tuwien.ac.at>
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1 changed files with 3 additions and 5 deletions
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@ -94,7 +94,7 @@ bool uploadDiveLogsDE::prepareDives(const QString &tempfile, bool selected)
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for_each_dive (i, dive) {
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char filename[PATH_MAX];
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int streamsize;
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const char *membuf;
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char *membuf;
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xmlDoc *transformed;
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struct zip_source *s;
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struct membufferpp mb;
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@ -137,14 +137,12 @@ bool uploadDiveLogsDE::prepareDives(const QString &tempfile, bool selected)
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if (ds) {
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put_format(&mb, "</divelog>\n");
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}
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membuf = mb_cstring(&mb);
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streamsize = mb.len;
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/*
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* Parse the memory buffer into XML document and
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* transform it to divelogs.de format, finally dumping
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* the XML into a character buffer.
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*/
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xmlDoc *doc = xmlReadMemory(membuf, streamsize, "divelog", NULL, 0);
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xmlDoc *doc = xmlReadMemory(mb.buffer, mb.len, "divelog", NULL, 0);
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if (!doc) {
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qWarning() << errPrefix << "could not parse back into memory the XML file we've just created!";
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report_error(tr("internal error").toUtf8());
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@ -171,7 +169,7 @@ bool uploadDiveLogsDE::prepareDives(const QString &tempfile, bool selected)
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* Save the XML document into a zip file.
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*/
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snprintf(filename, PATH_MAX, "%d.xml", i + 1);
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s = zip_source_buffer(zip, membuf, streamsize, 1);
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s = zip_source_buffer(zip, membuf, streamsize, 1); // frees membuffer!
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if (s) {
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int64_t ret = zip_add(zip, filename, s);
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if (ret == -1)
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