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84166a4ee7
It turns out that we are starting to have users that have logs that go back that far. It won't be common, but let's get it right anyway. NOTE! With us now supporting dates earlier in 1900, this also makes "utc_mktime()" always add the "1900" to the year field. That way we avoid ever using the fairly ambiguous two-digit shorthand. It didn't use to be all that ambiguous when we knew that any two-digit number less than 70 had to be 2000+. Now that we support going back to earlier in the last centiry, that certainty is eroding. Signed-off-by: Linus Torvalds <torvalds@linux-foundation.org> Signed-off-by: Dirk Hohndel <dirk@hohndel.org>
134 lines
3.3 KiB
C
134 lines
3.3 KiB
C
#include <string.h>
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#include "dive.h"
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/*
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* The date handling internally works in seconds since
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* Jan 1, 1900. That avoids negative numbers which avoids
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* some silly problems.
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*
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* But we then use the same base epoch base (Jan 1, 1970)
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* that POSIX uses, so that we can use the normal date
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* handling functions for getting current time etc.
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*
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* There's 25567 dats from Jan 1, 1900 to Jan 1, 1970.
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*
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* NOTE! The SEC_PER_DAY is not so much because the
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* number is complicated, as to make sure we always
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* expand the type to "timestamp_t" in the arithmetic.
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*/
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#define SEC_PER_DAY ((timestamp_t) 24*60*60)
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#define EPOCH_OFFSET (25567 * SEC_PER_DAY)
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/*
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* Convert 64-bit timestamp to 'struct tm' in UTC.
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*
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* On 32-bit machines, only do 64-bit arithmetic for the seconds
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* part, after that we do everything in 'long'. 64-bit divides
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* are unnecessary once you're counting minutes (32-bit minutes:
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* 8000+ years).
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*/
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void utc_mkdate(timestamp_t timestamp, struct tm *tm)
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{
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static const unsigned int mdays[] = {
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31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31,
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};
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static const unsigned int mdays_leap[] = {
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31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31,
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};
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unsigned long val;
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unsigned int leapyears;
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int m;
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const unsigned int *mp;
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memset(tm, 0, sizeof(*tm));
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// Midnight at Jan 1, 1970 means "no date"
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if (!timestamp)
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return;
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/* Convert to seconds since 1900 */
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timestamp += EPOCH_OFFSET;
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/* minutes since 1900 */
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tm->tm_sec = timestamp % 60;
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val = timestamp /= 60;
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/* Do the simple stuff */
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tm->tm_min = val % 60;
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val /= 60;
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tm->tm_hour = val % 24;
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val /= 24;
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/* Jan 1, 1900 was a Monday (tm_wday=1) */
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tm->tm_wday = (val + 1) % 7;
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/*
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* Now we're in "days since Jan 1, 1900". To make things easier,
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* let's make it "days since Jan 1, 1904", since that's a leap-year.
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* 1900 itself was not. The following logic will get 1900-1903
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* wrong. If you were diving back then, you're kind of screwed.
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*/
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val -= 365*4;
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/* This only works up until 2099 (2100 isn't a leap-year) */
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leapyears = val / (365 * 4 + 1);
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val %= (365 * 4 + 1);
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tm->tm_year = 1904 + leapyears * 4;
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/* Handle the leap-year itself */
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mp = mdays_leap;
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if (val > 365) {
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tm->tm_year++;
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val -= 366;
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tm->tm_year += val / 365;
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val %= 365;
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mp = mdays;
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}
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for (m = 0; m < 12; m++) {
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if (val < *mp)
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break;
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val -= *mp++;
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}
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tm->tm_mday = val + 1;
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tm->tm_mon = m;
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}
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timestamp_t utc_mktime(struct tm *tm)
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{
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static const int mdays[] = {
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0, 31, 59, 90, 120, 151, 181, 212, 243, 273, 304, 334
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};
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int year = tm->tm_year;
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int month = tm->tm_mon;
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int day = tm->tm_mday;
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int days_since_1900;
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timestamp_t when;
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/* First normalize relative to 1900 */
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if (year < 50)
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year += 100;
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else if (year > 1900)
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year -= 1900;
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if (year < 0 || year > 129) /* algo only works for 1900-2099 */
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return 0;
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if (month < 0 || month > 11) /* array bounds */
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return 0;
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if (month < 2 || (year && year % 4))
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day--;
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if (tm->tm_hour < 0 || tm->tm_min < 0 || tm->tm_sec < 0)
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return 0;
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/* This works until 2099 */
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days_since_1900 = year * 365 + (year - 1) / 4;
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/* Note the 'day' fixup for non-leapyears above */
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days_since_1900 += mdays[month] + day;
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/* Now add it all up, making sure to do this part in "timestamp_t" */
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when = days_since_1900 * SEC_PER_DAY;
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when += tm->tm_hour * 60 * 60 + tm->tm_min * 60 + tm->tm_sec;
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return when - EPOCH_OFFSET;
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}
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